(v^2+v-12)/(v^2+6v+8)/(2v-6)/(v+2)

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Solution for (v^2+v-12)/(v^2+6v+8)/(2v-6)/(v+2) equation: 


D( v )

v^2+6*v+8 = 0

v+2 = 0

2*v-6 = 0

v^2+6*v+8 = 0

v^2+6*v+8 = 0

v^2+6*v+8 = 0

DELTA = 6^2-(1*4*8)

DELTA = 4

DELTA > 0

v = (4^(1/2)-6)/(1*2) or v = (-4^(1/2)-6)/(1*2)

v = -2 or v = -4

v+2 = 0

v+2 = 0

v+2 = 0 // - 2

v = -2

2*v-6 = 0

2*v-6 = 0

2*v-6 = 0 // + 6

2*v = 6 // : 2

v = 6/2

v = 3

v in (-oo:-4) U (-4:-2) U (-2:3) U (3:+oo)

(((v^2+v-12)/(v^2+6*v+8))/(2*v-6))/(v+2) = 0

(v^2+v-12)/((v^2+6*v+8)*(2*v-6)*(v+2)) = 0

v^2+v-12 = 0

v^2+v-12 = 0

DELTA = 1^2-(-12*1*4)

DELTA = 49

DELTA > 0

v = (49^(1/2)-1)/(1*2) or v = (-49^(1/2)-1)/(1*2)

v = 3 or v = -4

(v+4)*(v-3) = 0

v^2+6*v+8 = 0

v^2+6*v+8 = 0

DELTA = 6^2-(1*4*8)

DELTA = 4

DELTA > 0

v = (4^(1/2)-6)/(1*2) or v = (-4^(1/2)-6)/(1*2)

v = -2 or v = -4

(v+4)*(v+2) = 0

((v+4)*(v-3))/((v+4)*(v+2)^2*(2*v-6)) = 0

( v+4 )

v+4 = 0 // - 4

v = -4

( v-3 )

v-3 = 0 // + 3

v = 3

v in { -4} 

v in { 3} 

v belongs to the empty set

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